How do you find the slope and intercept of $4 (3 x + 9) - 3 (5 y + 7) = 11$ $4(3x+9) - 3(5y+7)=11$ ?

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Answer 1 · 2017-03-19T11:20:11

the slope is $\frac{4}{5}$ $4/5$ and the intercept is $\frac{4}{15}$ $4/15$

First let's multiply and get the form $y = m x + n$ $y=mx+n$ where $m$ $m$ is the slope and $n$ $n$ is the intercept:

$12 x + 36 - 15 y - 21 = 11$ $12x+36-15y-21=11$

$15 y = 12 x + 36 - 21 - 11$ $15y=12x+36-21-11$

$15 y = 12 x + 4$ $15y=12x+4$

$y=cancel12^4/cancel15^5x+4/15$

$y=4/5x+4/15$

Then the slope is $4/5$ and the intercept is $4/15$

How do you find the slope and intercept of 4(3x+9) - 3(5y+7)=114(3x+9)−3(5y+7)=114(3x+9) - 3(5y+7)=11?