How do you simplify $\frac { 2x - 3} { 4x ^ { 2} + 4x } - \frac { 4} { 2x }$ ?

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Answer 1 · 2017-03-25T05:58:08

$(-6x-11)/(4x(x+1))$

First, let's factor $4x^2+4x=4x(x+1)$ and substitute:

$(2x-3)/(4x(x+1))-4/(2x)$

$=(2x-3-4*2*(x+1))/(4x(x+1))$

$=(2x-3-8x-8)/(4x(x+1))$

$=(-6x-11)/(4x(x+1))$

How do you simplify \frac { 2x - 3} { 4x ^ { 2} + 4x } - \frac { 4} { 2x }\frac { 2x - 3} { 4x ^ { 2} + 4x } - \frac { 4} { 2x }?