Question

How do you solve `(2c + 1) ( c - 5) = 0`?

Answer 1

#2c^2 -9c -5

Explanation:

Using the FOIL method (First Outside Inside Last)

Multiply 2c by c, you get #2c^2

Then multiply the outsides, -5 by 2c, you get -10c

Next multiply the insides, c by 1 you get c (or 1c)

Lastly, multiply the last, -5 by 1, you get -5

Write them down you would have

#2c^2 -10c + c -5

Add like terms, you get

#2c^2 -9c -5