How do you divide $\frac { 6y ^ { 2} + 8y - 4} { 2y + 2}$ ?

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Answer 1 · 2017-03-27T04:43:41

$Q(x)=3x+1$
$R=-3$

First you could factor and simplify:

$(cancel2(3y^2+4y-2))/(cancel2(y+1))$

Then you could apply the Ruffini rule:

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How do you divide \frac { 6y ^ { 2} + 8y - 4} { 2y + 2}\frac { 6y ^ { 2} + 8y - 4} { 2y + 2}?