How do you factor #4x^2+17x-15#?

1 Answer
Mar 29, 2017

Use the slide and divide method to get #(4x-3)(x+5)#.

Explanation:

YouTube

We'd use the slide and divide method.

Start by taking the #a# value, #4#, and multiply it (also called sliding) with the #c# value, #-15#. Now we're working with the equation #x^2+17x-60#.

Then we'd factor it as normal, to get #(x+20)(x-3)#. We have to bring the four back, and divide it from the #20# or the #-3#.

We'd get #(x+(20)/4)# and #(x-(3)/4)#. We only have to divide from one binomial though, and the #20# is easiest to work with.

We'd then have #20/4=5#, so we'd end up with (x+5).

We'd multiply the last #4#, from the second binomial, over to #x#, and get #4x-3#.

Combine the two to get #(4x-3)(x+5)#.