How do you write #9/20# as a decimal?

Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
2 Answers
Mar 31, 2017

It is written 0.45
Details on how to make the change are given below...

Explanation:

To do the conversion, you could change it to a fraction that has 100 as the denominator. That new fraction would be easy to write as a decimal.

#9/20 xx 5/5 = 45/100#

which, in decimal form is 0.45

Mar 31, 2017

The decimal form is #.45#

Explanation:

You'd need to convert the fraction into a decimal.

Multiply the denominator, which is #20#, by #5# to get #100#.

Multiply the numerator, #9#, by #5# as well to get #45#.

Our fraction is now #45/100#. The decimal form is #.45#