How do you factor #x^2+14x+45#?

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Answer 1 · 2017-03-31T20:01:27

#(x+5)(x+9)#

In order to the trinomial #x^2 + 14x + 45#

Begin by finding the factors for the first term

#x^2 = x*x#

Place those factors as the first term in each parenthesis

#(x_ _ )(x _ _ )#

Since both signs of the trinomial are positive you will be adding the factors and both signs will be positive.

#(x + _ _)(x + _ _ )#

Now determine the factors of the third term

# 45 = 1*45, 3*15, 5*9#

We need the factors that will add up to the middle term
#14 = 5 + 9#

Place these factors as the second term in each of the parenthesis.

#(x + 5)(x + 9)#

Answer 2 · 2017-03-31T20:03:31

#(x+5)(x+9)#

The two numbers that add up to #14#, and multiply to #45# and #9# and #5#.

#(x+5)(x+9)#

Answer 3 · 2017-03-31T20:03:31

#(x+5)(x+9)#

The two numbers that add up to #14#, and multiply to #45# and #9# and #5#.

#(x+5)(x+9)#