How do you solve pp−2−12=33p−6?

2 Answers
Astralboy
Apr 14, 2017

p=0

Explanation:

Find a common denominator.

I can see that 3p−6 is actually 3(p−2) There's also a 2 in 12. So a common denominator is 6(p−2)

Take this common denominator and multiply everything by that:

6p−3(p−2)=6

Distribute the 3

6p−3p+6=6

Combine the ps:

3p+6=6

Subtract 6 on both sides:

3p=0

Divide 3 on both sides to solve for p:

p=0

Plug p=0 back into the equation to make sure it works:

(00−2)−(12)=33(0)−6

−12=3−6

Simplifying 3−6 would get −12 so the answer works!

Andrés G.
Apr 14, 2017

p=0

Explanation:

Multiply both sides by 3p−6:
12(6−3p)+p(3p−6)p−2=3

Rewrite the left hand side by combining fractions. 12(6−3p)+p(3p−6)p−2=3(p+2)2:

3(p+2)2=3

Multiply both sides by 23:
p+2=2

Subtract 2 from both sides:
Answer:
p=0

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