How do you solve #(x - 25) ^ { \frac { 2} { 3} } = 16#?

1 Answer
David L.
Apr 17, 2017

#x=89#

Explanation:

Raise both sides of the problem to the power of #3/2#, doing so reduces the exponent on the LHS to the power of #1#, and allows for a simplier problem.

#[(x-25)^(2/3)]^(3/2)=16^(3/2)#

#(x-25)^1=64#

#x-25=64#

#x=89#

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