How do you solve ${(x - 25)}^{\frac{2}{3}} = 16$ $(x - 25) ^ { \frac { 2} { 3} } = 16$ ?

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How do you solve ${(x - 25)}^{\frac{2}{3}} = 16$ $(x - 25) ^ { \frac { 2} { 3} } = 16$ ?

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Answer 1 · 2017-04-17T05:04:47

$x = 89$ $x=89$

Explanation:

Raise both sides of the problem to the power of $\frac{3}{2}$ $3/2$ , doing so reduces the exponent on the LHS to the power of $1$ $1$ , and allows for a simplier problem.

${[{(x - 25)}^{\frac{2}{3}}]}^{\frac{3}{2}} = 16^{\frac{3}{2}}$ $[(x-25)^(2/3)]^(3/2)=16^(3/2)$

${(x - 25)}^{1} = 64$ $(x-25)^1=64$

$x - 25 = 64$ $x-25=64$

$x = 89$ $x=89$

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How do you solve ${(x - 25)}^{\frac{2}{3}} = 16$ $(x - 25) ^ { \frac { 2} { 3} } = 16$ ?

1 Answer

Explanation:

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