Question

Question #0e146

Answer 1

1

Explanation:

First, you would substitute `cotx=cosx/sinx`, then you get the expression:

`sin^2x+sin^2xcot^2x=sin^2x+cancel(sin^2x)cos^2x/cancel(sin^2x)`

and you would simplify and get:

`sin^2x+cos^2x=1`