Question

Question #a46f3

Answer 1

(b) increase, is the correct answer.

Explanation:

Let the EMF of battery be `V_o`.
Power dissipated by the resistor is `V_o^2/R`.

Since the value of resistance is decreased. Let the new resistance be `R'`.
`therefore` power dissipated by the new resistor is `V_o^2/(R')`.

Now `R' < R`
`=> 1/(R') > 1/R`

`=> color(red)(V_o^2/(R') > V_o^2/R)`

`therefore` on decreasing the value of resistance, the power dissipated by resistor increases.

(b) increase, is the correct answer.