How do you solve $\frac{x}{x - 1} = \frac{2}{x - 1}$ $\frac { x } { x - 1} = \frac { 2} { x - 1}$ ?

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Answer 1 · 2017-04-24T18:33:37

$x = 2$ $x=2$

$\frac{x}{x - 1} = \frac{2}{x - 1}$ $x/(x-1)=2/(x-1)$

Since we have common denominators we can subtract without changing anything

Move $\frac{2}{x - 1}$ $2/(x-1)$ to the other side of the equals sign as a negative

$\frac{x}{x - 1} - \frac{2}{x - 1} = 0$ $x/(x-1)-2/(x-1)=0$

This also equals

$\frac{x - 2}{x - 1} = 0$ $(x-2)/(x-1)=0$

Multiply both sides by $(x - 1)$ $(x-1)$ to remove the denominator

$cancel(x-1)((x-2)/cancel(x-1))=cancel(0(x-1))$

$x-2=0$

$x=2$

VERIFY YOUR ANSWER

Since $x=2$ ,

$x/(x-1)=2/(x-1)$

$((2))/((2)-1)=2/((2)-1)$

$2/1=2/1$

$2=2$

How do you solve \frac { x } { x - 1} = \frac { 2} { x - 1}xx−1=2x−1\frac { x } { x - 1} = \frac { 2} { x - 1}?