How do you solve 0= ( x - 8) ^ { 2} - 490=(x−8)2−49?
1 Answer
Perform opposite operations to the
Explanation:
Basically, all we have to do is perform opposite operations to the
So first off, let's move the
0=(x-8)^2-490=(x−8)2−49
49=(x-8)^249=(x−8)2
Now, let's square root the
7=x-87=x−8
Now, we move the
15=x15=x
We now know that
0=(x-8)^2-490=(x−8)2−49
0=(15-8)^2-490=(15−8)2−49
0=(7)^2-490=(7)2−49
0=49-490=49−49
0=00=0
We get the same answer! Therefore, we can conclude that
Hope this helps :)