Question

How do you solve the system of equations `y=4x+6` and `3x+y=41`?

Answer 1

`x = 5, y=26`

Explanation:

There is 3 ways of doing this problem: Substitution, Elimination or Graphing.
For this problem, substitution would be the easiest way because one equation is already solved.
All you have to do is plug `y = 4x + 6` into the 2nd equation.

The whole thing would turn out looking like: `3x+ (4x + 6) = 41`

Because 3x and 4x are the same, you would add them together and would get: `7x + 6 = 41`

Then bring the 6 over to the other side of the equal sign. Subtract 41 and 6 to get 35.
That would look like: `7x = 35`

Finally, divide 35 and 7 to get 5.
`35divide 7 = 5`
`x = 5`

Solve for `y` by substituting in the `x` value into one of the original equations:

`y=4x+6`

`y=4(5)+6=26`

graph{(y-(4x+6))(3x+y-41)=0 [-5, 10, 15, 30]}