Question

How do you multiply `3x^2y^2z(7x^2+2y+z+4w)`?

Answer 1

`21x^4y^2z+6x^2y^3z+3x^2y^2z^2+12x^2y^2zw`

Explanation:

Multiply each part of `7x^2+2y+z+4w` by `3x^2y^2z`
`3x^2y^2z(7x^2)=21x^4y^2z`
`3x^2y^2z(2y)=6x^2y^3z`
`3x^2y^2z(z)=3x^2y^2z^2`
`3x^2y^2z(4w)=12x^2y^2zw`

Then you add each part to get
`21x^4y^2z+6x^2y^3z+3x^2y^2z^2+12x^2y^2zw`