What is #sqrt(48)# ?
2 Answers
Explanation:
Like Asma said you can calculate the square root on a calculator for the exact amount. But sometimes a professor will ask you to simplify. This will be very useful in the future.
We want to check if there is a number with a perfect square that is a multiple of the number in our square root. In this case, there is one.
Since
Explanation:
Note that:
#48 = 4^2*3#
So we find:
#sqrt(48) = sqrt(4^2*3) = sqrt(4^2)sqrt(3) = 4sqrt(3)#
That is the "simplest" form.
In fact, since
#sqrt(48) = [6;bar(1,12)] = 6+1/(1+1/(12+1/(1+1/(12+1/(1+1/(12+..))))))#
To get rational approximations, we can truncate this continued fraction early (preferably just before a "
For example:
#sqrt(48) ~~ 6+1/(1+1/(12+1/1)) = 97/14 = 6.9bar(285714)#
#sqrt(48) ~~ 6+1/(1+1/(12+1/(1+1/(12+1/1)))) = 1351/195 = 6.9bar(282051)#
#sqrt(48) ~~ 6+1/(1+1/(12+1/(1+1/(12+1/(1+1/(12+1/1)))))) = 18817/2716 ~~ 6.92820324#
A calculator tells me that it is closer to