How do you subtract $2 x^{2} - 6 x - 4$ $2x^2-6x-4$ from $4 x^{2} - 4 x + 3$ $4x^2-4x+3$ ?

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Answer 1 · 2017-04-28T22:49:10

$2 x^{2} + 2 x + 7$ $2x^2+2x+7$

We combine like terms:
$4 x^{2} - 2 x^{2} = 2 x^{2}$ $4x^2-2x^2=2x^2$
$- 4 x - (- 6 x) = 2 x$ $-4x-(-6x)=2x$
$3 - (- 4) = 7$ $3-(-4)=7$

We add the terms together and our answer is $2 x^{2} + 2 x + 7$ $2x^2+2x+7$

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