Question

Question #e9dfa

Answer 1

Dimensions are : width `sqrt(13)`, length `5sqrt(13)`

Explanation:

Original rectangle:
let width be `w`, and length be `5w`

New rectangle:
new width `w-1`, new length `5w+5`
So, new area :`(5w+5)*(w-1) = 60`
`5(w+1)(w-1)=60`
`5(w^2 -1)=60`
`w^2-1 = 12`
`w^2 = 13`
`w = \pm sqrt(13)`
since width cannot be negative, `w = sqrt(13)` and the length is `5w = 5sqrt(13)`