Question #e9dfa

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Question #e9dfa

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Answer 1 · 2017-05-03T16:26:39

Dimensions are : width $\sqrt{13}$ $sqrt(13)$ , length $5 \sqrt{13}$ $5sqrt(13)$

Explanation:

Original rectangle:
let width be $w$ $w$ , and length be $5 w$ $5w$

New rectangle:
new width $w - 1$ $w-1$ , new length $5 w + 5$ $5w+5$
So, new area : $(5 w + 5) \cdot (w - 1) = 60$ $(5w+5)*(w-1) = 60$
$5 (w + 1) (w - 1) = 60$ $5(w+1)(w-1)=60$
$5 (w^{2} - 1) = 60$ $5(w^2 -1)=60$
$w^{2} - 1 = 12$ $w^2-1 = 12$
$w^{2} = 13$ $w^2 = 13$
$w = \pm \sqrt{13}$ $w = \pm sqrt(13)$
since width cannot be negative, $w = \sqrt{13}$ $w = sqrt(13)$ and the length is $5 w = 5 \sqrt{13}$ $5w = 5sqrt(13)$

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