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Question #78d48

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May 7, 2017

Inverse of $2^{x}$ $2^x$ = $\frac{ln (x)}{ln (2)}$ $ln(x)/ln(2)$

Explanation:

Any time you find the inverse of an exponential function, that will result in a natural log (ln).

Additionally when finding an inverse you should swap your x and y values and solve for y.

Inverse of $2^{x}$ $2^x$ :

$x = (\frac{ln (y)}{ln (2)})$ $x= (ln(y)/ln(2))$

Substitute y = x

Inverse of $2^{x}$ $2^x$ = $\frac{ln (x)}{ln (2)}$ $ln(x)/ln(2)$

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