How do you solve #\sqrt { 5- \frac { x } { 4} } = \sqrt { x + 8}#?

↳Redirected from "What are valence electrons?"
1 Answer
Mia
May 8, 2017

#x=-12/5#

Explanation:

#sqrt (5-x/4)=sqrt (x+8)#
#" "#
Squaring both sides:
#" "#
#(sqrt (5-x/4))^2=(sqrt (x+8))^2#
#" "#
#rArr5-x/4=x+8#
#" "#
#rArr-x/4-x=-5+8#
#" "#
#rArr-x/4-(4x)/4=+3#
#" "#
#rArr-(5x)/4=3#
#" "#
#rArr-5x=12#
#" "#
#rArrx=-12/5#

Related questions
Impact of this question
1217 views around the world
You can reuse this answer
Creative Commons License