How do you factor $4x^3-4x$ completely?

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Answer 1 · 2017-05-13T17:45:45

$4x(x^2-1)$

Factor out what is common in both terms, in this case the coefficant $4$ and $x$ and common to both terms

$4(x^3-x)$

$4x(x^2-1)$

How do you factor 4x^3-4x4x^3-4x completely?