How do you solve \frac { 1} { y } + \frac { 1} { y + 8} = \frac { 1} { 11}?

1 Answer
May 14, 2017

First, note that y cannot be equal to 0 or -8

Then, multiply both sides by 11*y*(y+8), you get :

11(y+8) + 11y = y(y+8)
<=>
22y+88 = y^2 + 8y
<=>
y^2 - 14y - 88 = 0

Then you have a quadratic equation.