Question #0b840

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Answer 1 · 2017-05-17T16:59:04

$2.5 \cdot 4.8 = 12 k g m s^{- 1}$ $2.5*4.8=12kg m s^-1$

Given:
Mass is a scalar quantity:

$m = 2.5 kg$ $m = 2.5"kg"$

Velocity is a vector:

$\to v = 4.8 \frac{m}{s} South$ $vecv = 4.8"m"/"s"" South"$

Momentum is a vector in the same direction as the velocity vector:

$\to p = m (\to v)$ $vecp = m(vecv)$

Substitute in the given quantities:

$\to p = 2.5 kg (4.84 .8 \frac{m}{s} South)$ $vecp = 2.5"kg"(4.84.8"m"/"s"" South")$

$\to p = 12 \frac{kg m}{s} South$ $vecp = 12"kg m"/"s"" South"$