Question #f8198

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Question #f8198

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Answer 1 · 2017-05-19T14:13:21

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Explanation:

Phythagorean Identity:
${sin}^{2} (θ) + {cos}^{2} (θ) = 1$ $sin^2(theta)+cos^2(theta)=1$
$\frac{{sin}^{2} (θ) + {cos}^{2} (θ) = 1}{{sin}^{2} (θ)}$ $[sin^2(theta)+cos^2(theta)=1]/sin^2(theta)$
${cot}^{2} (θ) + 1 = {csc}^{2} (θ)$ $cot^2(theta)+1=csc^2(theta)$

Use it to solve the identity:

$1 + {csc}^{2} (θ) {cos}^{2} (θ)$ $1+csc^2(theta)cos^2(theta)$
$1 + \frac{{cos}^{2} (θ)}{{sin}^{2} (θ)}$ $1+cos^2(theta)/sin^2(theta)$
$1 + {cot}^{2} (θ)$ $1+cot^2(theta)$
${csc}^{2} (θ) = R H S$ $csc^2(theta)=RHS$

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Question #f8198

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