Question #5285e

1 Answer
Altrigeos
May 21, 2017

33

Explanation:

lim_(x->∞)(2^(x+1)+3^(x+1))/(2^x+3^x)

Divide by the highest Power:
lim_(x->∞)(2^(x+1)/(3^x)+3)/((2^x)/3^x+1)

(lim_(x->∞)(2^(x+1)/3^x+1))/(lim_(x->∞)((2^x)/3^x+1))=(0+3)/(0+1)=3/1=3

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