What is the distance between #(1,-4)# and #(7,5)#?

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Answer 1 · 2017-05-31T13:17:31

10.82

#sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)#

First arrange the coordinates as #x_1#, #y_1# etc..

#x_1 = 1#
#y_1 = -4#
#x_2 = 7#
#y_2 = 5#

Now substitute the values into the equation:

#sqrt((7-1)^2 + (5-(-4))^2)#

= #sqrt(36 +81)#

= #sqrt(117)#

= 10.82