Distance Formula
Key Questions
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Answer:
Let's see.
Explanation:
I have drawn a graph in which there are two points
#color(red)(p_1(x_1,y_1))" and "color(red)(p_2(x_2,y_2)# .- We can easily say that
#" "bar(OD)=x_1" ; "bar(OE)=x_2" ; "bar(AD)=y_1" ; "bar(EB)=y_2#
We also have a rectangle
#square OCED# . So,#color(red)(bar(AC)=bar(DE)) " and "color(red)(bar(AD)=bar(CE)# Now,
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#bar(AC)=bar(DE)=bar(OE)-bar(OD)=(x_2 -x_1)# -
#bar(BC)=bar(BE)-bar(CE)=bar(BE)-bar(AD)=(y_2-y_1)#
With the help of Pythagorean theorem,
#bar(AB)^2=bar(BC)^2+bar(AC)^2# #bar(AB)^2=(x_2-x_1)^2+(y_2-y_1)^2# #bar(AB)=sqrt((x_2-x_1)^2+(y_2-y_1)^2# N.B:- As it is a square value , you may take
#(x_1-x_2)# or,#(x_2-x_1)# . I mean you have to take difference.That's#(x_1~x_2)# So, the required formula is proved that
If the distance between two points
#color(green)(p_1(x_1,y_1)# and#color(green)(p_2(x_2,y_2)# is#color(red)(r# ,then,
#color(red)(ul(bar(|color(green)(r=sqrt((x_1-x_2)^2+(y_1-y_2)^2))|# Hope it helps...
Thank you... - We can easily say that
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Distance Formula
The distance
#D# between two points#(x_1,y_1)# and#(x_2,y_2)# can be found by#D=sqrt{(x_2-x_1)^2+(y_2-y_1)^2}#
Example
Find the distance between the points
#(1,-2)# and#(5,1)# .Let
#(x_1,y_1)=(1,-2)# and#(x_2,y_2)=(5,1)# .By Distance Formula above,
#D=sqrt{(5-1)^2+[1-(-2)]^2}=sqrt{16+9}=sqrt{25}=5#
I hope that this was helpful.
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Given the two points
#(x_1, y_1)# and#(x_2, y_2)# the distance between these points is given by the formula:#d=sqrt((x_2-x_1)^2+(y_2-y_1)^2 )# All you have to do is plug in the given points given to the distance formula and solve.
Questions
Radicals and Geometry Connections
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Graphs of Square Root Functions
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Simplification of Radical Expressions
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Addition and Subtraction of Radicals
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Multiplication and Division of Radicals
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Radical Equations
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Pythagorean Theorem and its Converse
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Distance Formula
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Midpoint Formula
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Measures of Central Tendency and Dispersion
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Stem-and-Leaf Plots
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Box-and-Whisker Plots