What is the distance between $(3,13,10)$ and $(3,-17,-1)$ ?

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Answer 1 · 2016-04-07T06:16:55

Distance between $(3,13,10)$ and $(3,-17,-1)$ is $31.95$ units.

Distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by $sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$ .

Hence distance between $(3,13,10)$ and $(3,-17,-1)$ is

$sqrt((3-3)^2+((-17)-13)^2+((-1)-10)^2)=sqrt((0)^2+(-17-13)^2+(-1-10)^2)$

= $sqrt((0)^2+(-30)^2+(-11)^2)=sqrt(0+900+121)$

= $sqrt1021=31.95$

What is the distance between (3,13,10)(3,13,10) and (3,-17,-1)(3,-17,-1)?