What is the distance between (3,15,2) and (4,15,4)?

1 Answer
Feb 16, 2016

859.2195

Explanation:

Use the three-dimensional distance formula, which can be derived by applying the Pythagorean Theorem twice. Given two points in 3-dimensional space written in rectangular coordinates (x1,y1,z1) and (x2,y2,z2), the distance is:

dist=(x1x2)2+(y1y2)2+(z1z2)2

For the problem at hand, this becomes

dist=72+02+62=49+36=859.2195.