What is the distance between $(3, –1, 1)$ and $(–4, 0, 2)$ ?

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Answer 1 · 2016-02-13T10:09:06

We must calculate distance as the usual way, using generalized Pythagoras theorem.

For generalized Pythagoras theorem, we have:

$d^2 = (x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2$

where $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ are both points.

Hence:
$d^2 = (-4-3)^2+(0-(-1))^2+(2-1)^2 = 51$

And taking square roots:
$d = sqrt{51}$

What is the distance between (3, –1, 1) (3, –1, 1) and (–4, 0, 2) (–4, 0, 2) ?