What is the distance between $(3, 6, - 2)$ $(3,6,-2)$ and $(- 3, - 3, - 1)$ $(-3,-3,-1)$ ?

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What is the distance between $(3, 6, - 2)$ $(3,6,-2)$ and $(- 3, - 3, - 1)$ $(-3,-3,-1)$ ?

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Answer 1 · 2015-12-01T11:43:45

distance $= 6 \sqrt{3}$ $= 6sqrt(3)$

Explanation:

Given $(x, y, z)$ $(x,y,z)$ coordinate points $(3, 6, - 2)$ $(3,6,-2)$ and $(- 3, - 3, - 1)$ $(-3,-3,-1)$

$(δ x, δ y, δ z) = (6, 9, 1)$ $(deltax,deltay,deltaz) = (6,9,1)$

and the distance between the points
$= \sqrt{6^{2} + 9^{2} + 1^{1}} = \sqrt{36 + 81 + 1} = \sqrt{118} = 6 \sqrt{3}$ $= sqrt(6^2+9^2+1^1) = sqrt(36+81+1) = sqrt(118) = 6sqrt(3)$

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What is the distance between $(3, 6, - 2)$ $(3,6,-2)$ and $(- 3, - 3, - 1)$ $(-3,-3,-1)$ ?

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Explanation:

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What is the distance between (3,6,−2)(3,6,-2) and (−3,−3,−1)(-3,-3,-1)?

1 Answer

Explanation:

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What is the distance between $(3, 6, - 2)$ $(3,6,-2)$ and $(- 3, - 3, - 1)$ $(-3,-3,-1)$ ?