What is the distance between (15,3,-4) and (21,-6,-2)?

1 Answer
Apr 28, 2016

distance=11

Explanation:

A=(15,3,-4)

a_x=15
a_y=3
a_z=-4

B=(21,-6,-2)

B_x=21
B_y=-6
B_z=-2

x^2=(B_x-A_x)^2

x^2=(21-15)^2" "x^2=6^2" "x^2=36

y^2=(B_y-A_y)^2

y^2=(-6-3)^2" "b_y^2=-9^2" "b_y^2=81

z^2=(B_z-A_z)^2

z^2=(-2+4)^2" "z^2=2^2" "z^2=4

distance=sqrt(x^2+y^2+z^2)

distance=sqrt(36+81+4)

distance=11