What is the distance between $(5, –6, 4)$ and $(4, –4, –2)$ ?

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Answer 1 · 2016-03-17T11:36:38

Distance $=sqrt 41$ units

Distance $=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2) =sqrt((4-5)^2+(-4+6)^2+(-2-4)^2)=sqrt(1+4+36)=sqrt41$ [Ans]

What is the distance between (5, –6, 4) (5, –6, 4) and (4, –4, –2)(4, –4, –2)?