What is the distance between $(8,-7,-4)$ and $(9,2,2)$ ?

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Answer 1 · 2016-02-24T01:39:49

$D= sqrt(118) ~= 10.86$

Note: The distance formula in 3D is

$D= sqrt((x_1-x_2)^2 + (y_1-y_2)^2 +(z_1-z_2)^2)$

We are given ordered triplet in $x, y, z$ , as follow

$(8, -7, -4) " and " (9, 2, 2)$

$D= sqrt((8-9)^2 + (-7-2)^2 +(-4-2)^2)$

$D= sqrt((-1)^2 + (-9)^2 +(-6)^2)$

$D= sqrt((1) + (81) +(36))$

$D= sqrt(118) ~= 10.86$

What is the distance between (8,-7,-4)(8,-7,-4) and (9,2,2)(9,2,2)?