What is the distance between $(2, 7, 4)$ $(2,7,4)$ and $(7, 4, 1)$ $(7,4,1)$ ?

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What is the distance between $(2, 7, 4)$ $(2,7,4)$ and $(7, 4, 1)$ $(7,4,1)$ ?

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Answer 1 · 2016-06-21T11:15:35

Distance is $6.56 (2 d p) u n i t s$ $6.56(2dp) units$

Explanation:

Distance $D = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}} = \sqrt{{(7 - 2)}^{2} + {(4 - 7)}^{2} + {(1 - 4)}^{2}} = \sqrt{25 + 9 + 9} = \sqrt{43} = 6.56 (2 d p) u n i t s$ $D= sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2) =sqrt((7-2)^2+(4-7)^2+(1-4)^2)=sqrt(25+9+9) =sqrt43 =6.56(2dp) units$ [Ans]

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What is the distance between $(2, 7, 4)$ $(2,7,4)$ and $(7, 4, 1)$ $(7,4,1)$ ?

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