What is the distance between $(–2, 1, 3)$ and $(2, –3, 1)$ ?

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Answer 1 · 2018-05-04T06:11:23

$6$

The distance between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ is given by the formula:

$d = sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

In our example, putting $(x_1, y_1, z_1) = (-2, 1, 3)$ and $(x_2, y_2, z_2) = (2, -3, 1)$ , we find distance:

$d = sqrt((2-(-2))^2+(-3-1)^2+(1-3)^2)$

$color(white)(d) = sqrt(4^2+4^2+2^2) = sqrt(36) = 6$

What is the distance between (–2, 1, 3) (–2, 1, 3) and (2, –3, 1) (2, –3, 1) ?