What is the distance between (10,15,-2)(10,15,−2) and (12,-2,15)(12,−2,15)?

1 Answer
Jim G.
Apr 26, 2018

sqrt582~~24.12" to 2 dec. places"√582≈24.12 to 2 dec. places

Explanation:

"using the 3-dimensional form of the "color(blue)"distance formula"using the 3-dimensional form of the distance formula

•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)∙xd=√(x2−x1)2+(y2−y1)2+(z2−z1)2

"let "(x_1,y_1,z_1)=(10,15,-2)" and "let (x1,y1,z1)=(10,15,−2) and

(x_2,y_2,z_2)=(12,-2,15)(x2,y2,z2)=(12,−2,15)

d=sqrt((12-10)^2+(-2-15)^2+(15+2)^2)d=√(12−10)2+(−2−15)2+(15+2)2

color(white)(d)=sqrt(4+289+289)=sqrt582~~24.12d=√4+289+289=√582≈24.12

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