What is the distance between $(- 12, 1, 3)$ $(-12,1,3)$ and $(- 6, 2, 1)$ $(-6,2,1)$ ?

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Answer 1 · 2017-02-07T19:16:09

The distance is $= \sqrt{41} = 6.4$ $=sqrt41=6.4$

The distance between 2 points $(x_{1}, y_{1}, z_{1})$ $(x_1,y_1, z_1)$ and $(x_{2}, y_{2}, z_{2})$ $(x_2,y_2,z_2)$ , is

$d = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}}$ $d=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

So,

$d = \sqrt{{(- 6 + 12)}^{2} + {(2 - 1)}^{2} + {(1 - 3)}^{2}}$ $d=sqrt((-6+12)^2+(2-1)^2+(1-3)^2)$

$= \sqrt{36 + 1 + 4}$ $=sqrt(36+1+4)$

$= \sqrt{41} = 6.4$ $=sqrt(41)=6.4$

What is the distance between (−12,1,3)(-12,1,3) and (−6,2,1)(-6,2,1)?