What is the distance between $(4, 3, 1)$ and $(3, 6, 2)$ ?

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Answer 1 · 2016-02-02T11:07:37

Distance = $sqrt 11 units$

The Distance Formula is $D=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$ or $D=sqrt((3-4)^2+(6-3)^2+(2-1)^2) = sqrt(1+9+1) =sqrt 11$ [Ans]

What is the distance between (4, 3, 1) (4, 3, 1) and (3, 6, 2) (3, 6, 2) ?