What is the distance between (9, 2, 0) and (8, 6, 2) ?
1 Answer
Mar 30, 2017
Explanation:
The distance formula for 3 dimensions is:
sqrt((Deltax)^2 + (Deltay)^2 + (Deltaz)^2)
In this case,
Deltax = 8 - 9 = -1
Deltay = 6 - 2 = 4
Deltaz = 2 - 0 = 2
So the distance is:
sqrt((-1)^2 + 4^2 + 2^2) = sqrt(1+16+4) = sqrt21