How do you find the distance between (3,2) and (1,-1)?

1 Answer
Sep 11, 2015

Distance between (3,2) and (1,-1) is sqrt(13)

Explanation:

(see image below)
enter image source here
The horizontal distance between (1,-1) and (3,2) is
color(white)("XXX")Delta x = abs(3-1) = 2

The vertical distance between (-1,-1) and (3,2) is
color(white)("XXX")Delta y = abs((-1)-2) = 3

By the Pythagorean Theorem the distance between (-1,1) and (3,2) is
color(white)("XXX")sqrt((Delta x)^2+(Delta y)^2)

color(white)("XXX")= sqrt(2^2+3^2)

color(white)("XXX")= sqrt(13)