What is the distance between $(3,2,-1)$ and $(5,-1,6)$ ?

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Answer 1 · 2016-05-01T19:47:57

$sqrt(62) ~~ 7.874$

The distance $d$ between $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ is given by the formula:

$d = sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

$=sqrt((5-3)^2+(-1-2)^2+(6-(-1))^2)$

$=sqrt(2^2+(-3)^2+7^2)$

$=sqrt(4+9+49)$

$=sqrt(62) ~~ 7.874$

What is the distance between (3,2,-1)(3,2,-1) and (5,-1,6)(5,-1,6)?