What is the distance between $(22, 25, 7)$ $(22,25,7)$ and $(31, 40, 0)$ $(31,40,0)$ ?

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What is the distance between $(22, 25, 7)$ $(22,25,7)$ and $(31, 40, 0)$ $(31,40,0)$ ?

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Answer 1 · 2018-04-13T10:39:19

$\sqrt{355} \approx 18.8$ $sqrt(355)~~18.8$

Explanation:

The distance between $(x_{1}, y_{1}, z_{1})$ $(x_1,y_1,z_1)$ and $(x_{2}, y_{2}, z_{2})$ $(x_2,y_2,z_2)$ is given by $\sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}}$ $sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

So for these two points we have:
$\sqrt{{(31 - 22)}^{2} + {(40 - 25)}^{2} + {(0 - 7)}^{2}} = \sqrt{{(9)}^{2} + {(15)}^{2} + {(- 7)}^{2}} = \sqrt{81 + 225 + 49} = \sqrt{355} \approx 18.8$ $sqrt((31-22)^2+(40-25)^2+(0-7)^2)=sqrt((9)^2+(15)^2+(-7)^2)=sqrt(81+225+49)=sqrt(355)~~18.8$

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What is the distance between $(22, 25, 7)$ $(22,25,7)$ and $(31, 40, 0)$ $(31,40,0)$ ?

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Explanation:

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What is the distance between $(22, 25, 7)$ $(22,25,7)$ and $(31, 40, 0)$ $(31,40,0)$ ?