What is the distance between $(–6, 3, 1)$ and $(–4, 0, 2)$ ?

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Answer 1 · 2016-04-22T18:04:54

$s=sqrt 14$

$A=(-6,3,1)$
$"where : " A_x=-6" "A_y=3" "A_z=1$

$B=(-4,0,2)$
$B_x=-4" "B_y=0" "B_z=2$

$"distance between (-6,3,1) and (-4,0,2) can be calculated using"$

$s=sqrt((B_x-A_x)^2+(B_y-A_y)^2+(B_z-A_z)^2)$

$s=sqrt((-4+6)^2+(0-3)^2+(2-1)^2)$

$s=sqrt(2^2+(-3^2)+1^2)$

$s=sqrt(4+9+1)$

$s=sqrt 14$

What is the distance between (–6, 3, 1) (–6, 3, 1) and (–4, 0, 2) (–4, 0, 2) ?