What is the distance between $(- 1, 14, 1)$ $(-1,14,1)$ and $(- 1, 4, - 2)$ $(-1,4,-2)$ ?

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Answer 1 · 2017-01-25T12:59:35

$= \sqrt{109}$ $=sqrt109$

$D i s tan c e = \sqrt{{(x - x_{1})}_{1}^{2} + {(y - y_{1})}_{1}^{2} + {(z - z_{1})}_{1}^{2}}$ $Distance=sqrt((x-x_1)^2+(y-y_1)^2+(z-z_1)^2$

$= \sqrt{{(- 1 - (- 1))}^{2} + {(14 - 4)}^{2} + {(1 - (- 2))}^{2}}$ $=sqrt((-1-(-1))^2+(14-4)^2+(1-(-2))^2$

$= \sqrt{{(0)}^{2} + {(10)}^{2} + {(3)}^{2}}$ $=sqrt((0)^2+(10)^2+(3)^2$

$= \sqrt{109}$ $=sqrt109$

What is the distance between (−1,14,1)(-1,14,1) and (−1,4,−2)(-1,4,-2)?