What is the distance between $(-2,1,-13)$ and $(4,3,-12)$ ?

Question

1429 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-03T19:33:02

$s=sqrt41$

$A=(-2,1,-13)$
$B=(4,3,-12)$

$A_x=-2$
$A_y=1$
$A_z=-13$

$B_x=4$
$B_y=3$
$B_z=-12$

$"distance between A and B can be calculated by formula:"$
$s=sqrt((B_x-A_x)^2+(B_y-A_y)^2+(B_z-A_z)^2)$

$s=sqrt((4+2)^2+(3-1)^2+(-12+13)^2)$

$s=sqrt(6^2+2^2+1^2)=sqrt(36+4+1)=sqrt(41)$

What is the distance between (-2,1,-13)(-2,1,-13) and (4,3,-12)(4,3,-12)?