What is the distance between $(3,-2,-2)$ and $(5,-4,-6)$ ?

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Answer 1 · 2018-04-03T16:20:47

I tried this:

The distance between the two points can be found using a kind of extended Pythagoras formula:

$d_(1_2)=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

so, using our coordinates given in the problem:

$d=sqrt((5-3)^2+[-4-(-2)]^2+[-6-(-2))^2]=sqrt(4+4+16)=sqrt(24)=4.89"units"$

What is the distance between (3,-2,-2)(3,-2,-2) and (5,-4,-6)(5,-4,-6)?