What is the distance between $(13, - 13, 1)$ $(13,-13,1)$ and $(22, - 1, 6)$ $(22,-1,6)$ ?

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What is the distance between $(13, - 13, 1)$ $(13,-13,1)$ and $(22, - 1, 6)$ $(22,-1,6)$ ?

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Answer 1 · 2018-03-06T13:14:43

$15.81$ $15.81$ units

Explanation:

For the distance between two points on a three-dimensional graph, the following formula is used:

$d = ∣ ∣ ∣ \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2} + {(z_{2} - z_{1})}_{2}^{2}} ∣ ∣ ∣$ $d=|sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)|$

Here, $(x_{1}, y_{2}, z_{1}) = (13, - 13, 1)$ $(x_1,y_2,z_1)=(13,-13,1)$ and $(x_{2}, y_{2}, z_{2}) = (22, - 1, 6)$ $(x_2,y_2,z_2)=(22,-1,6)$ .

Inputting:

$d = ∣ ∣ ∣ \sqrt{{(22 - 13)}^{2} + {(- 1 - (- 13))}^{2} + {(6 - 1)}^{2}} ∣ ∣ ∣$ $d=|sqrt((22-13)^2+(-1-(-13))^2+(6-1)^2)|$

$d = ∣ ∣ \sqrt{9^{2} + 12^{2} + 5^{2}} ∣ ∣$ $d=|sqrt(9^2+12^2+5^2)|$

$d = ∣ ∣ \sqrt{81 + 144 + 25} ∣ ∣$ $d=|sqrt(81+144+25)|$

$d = ∣ ∣ \sqrt{250} ∣ ∣$ $d=|sqrt(250)|$

$d = 15.81$ $d=15.81$ units

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What is the distance between $(13, - 13, 1)$ $(13,-13,1)$ and $(22, - 1, 6)$ $(22,-1,6)$ ?

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Explanation:

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What is the distance between (13,−13,1)(13,-13,1) and (22,−1,6)(22,-1,6)?

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What is the distance between $(13, - 13, 1)$ $(13,-13,1)$ and $(22, - 1, 6)$ $(22,-1,6)$ ?