What is the distance between #(13,-13,1)# and #(22,-1,6)#?

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Answer 1 · 2018-03-06T13:14:43

#15.81# units

For the distance between two points on a three-dimensional graph, the following formula is used:

#d=|sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)|#

Here, #(x_1,y_2,z_1)=(13,-13,1)# and #(x_2,y_2,z_2)=(22,-1,6)#.

Inputting:

#d=|sqrt((22-13)^2+(-1-(-13))^2+(6-1)^2)|#

#d=|sqrt(9^2+12^2+5^2)|#

#d=|sqrt(81+144+25)|#

#d=|sqrt(250)|#

#d=15.81# units