What is the distance between $(6, - 2)$ $(6,-2)$ and $(- 9, 13)$ $(-9,13)$ ?

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Answer 1 · 2015-12-29T07:32:39

$15 \sqrt{2}$ $15sqrt2$

$d = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$ $d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$(x_{1}, y_{1}) \to (6, - 2)$ $(x_1,y_1)rarr(6,-2)$

$(x_{2}, y_{2}) \to (- 9, 13)$ $(x_2,y_2)rarr(-9,13)$

Thus,

$d = \sqrt{{(- 9 - 6)}^{2} + (13 - {(- 2)}^{2})}$ $d=sqrt((-9-6)^2+(13-(-2)^2)$

$d = \sqrt{{(- 15)}^{2} + 15^{2}}$ $d=sqrt((-15)^2+15^2)$

$d = \sqrt{2 \cdot 15^{2}}$ $d=sqrt(2*15^2)$

$d = 15 \sqrt{2}$ $d=15sqrt2$

What is the distance between (6,-2)(6,−2)(6,-2) and (-9,13)(−9,13)(-9,13)?