What is the distance between $(–2, 2, 6)$ and $(4, –1, 2)$ ?

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Answer 1 · 2016-06-24T13:48:50

The distance between $(-2,2,6)$ and $(4,-1,2)$ is $7.81$ .

The distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Hence distance between $(-2,2,6)$ and $(4,-1,2)$ is

$sqrt((4-(-2))^2+((-1)-2)^2+(2-6)^2)$

= $sqrt(6^2+3^2+4^2)=sqrt(36+9+16)=sqrt61=7.81$ .

What is the distance between (–2, 2, 6) (–2, 2, 6) and (4, –1, 2)(4, –1, 2)?